Re: make fails to build on linux

[Manuel Bouyer <bouyer%antioche.eu.org@localhost>]

On Sat, Apr 17, 2021 at 10:44:36PM +0200, Jaromír Dole?ek wrote:
> Le sam. 17 avr. 2021 à 19:49, Manuel Bouyer <bouyer%antioche.eu.org@localhost> a écrit :
> >
> > On Sat, Apr 17, 2021 at 07:25:58PM +0200, Manuel Bouyer wrote:
> > > Hello
> > > trying a build.sh tools on linux I got:
> > > /dsk/l1/misc/bouyer/HEAD/clean/src/tools/compat/../../lib/libc/regex/regcomp.c:
> > > In function '__regex_wctype':
> > > /dsk/l1/misc/bouyer/HEAD/clean/src/tools/compat/../../lib/libc/regex/regcomp.c:254:2: error: 'for' loop initial declarations are only allowed in C99 mode
> > >   for (size_t i = 0; i < __arraycount(wctypes); i++) {
> > >     ^
> > > /dsk/l1/misc/bouyer/HEAD/clean/src/tools/compat/../../lib/libc/regex/regcomp.c:2
> > > 54:2: note: use option -std=c99 or -std=gnu99 to compile your code
> > >
> > > What is the right fix for this ?
> > >
> > > For now I just moved the declaration outside of the loop
> >
> > Well, the build fails later with the same error.
> > Using "-V HOST_CFLAGS=-std=gnu99" allows the tools to build; maybe
> > this should be the default ?
> 
> I think it would be sensible to use -std=c99 by default, yes. It's

it has to be gnu99; I tried c99 and it failed with some types not defined.

> strange that the Linux toolchain refuses it by default, do we force
> some other -std flag by default now by chance?

AFAIK no. But the toolchain on RLEL7 is quite old: 
gcc version 4.8.5 20150623 (Red Hat 4.8.5-44) (GCC)

-- 
Manuel Bouyer <bouyer%antioche.eu.org@localhost>
     NetBSD: 26 ans d'experience feront toujours la difference
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