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Re: mutex fault
On Mon, Nov 26, 2007 at 08:24:45PM +0900, Kazushi Marukawa wrote:
> Thanks for checking codes. As you requested, I ran the new
> kernel after compiling with -g option (call it netbsd1122g)
> and got crash trase of it. Unfortunately, it seems the
> same. The address is also the same, callout_softclock+0x24d.
>
> Disasseble of callout_softclock shows following (0x24d=589):
>
> 0xc043151a <callout_softclock+586>: call *0xffffffec(%ebp)
> 0xc043151d <callout_softclock+589>: movl $0xc098d594,(%esp)
> 0xc0431524 <callout_softclock+596>: call 0xc04db580 <mutex_spin_enter>
>
> Line numbers are:
> callout_softclock+586: kern/kern_timeout.c 604
> callout_softclock+589: kern/kern_timeout.c 605
> callout_softclock+596: kern/kern_timeout.c 605
>
> And here is the source code.
> 602 KERNEL_UNLOCK_ONE(curlwp);
> 603 } else
> 604 (*func)(arg);
> 605 mutex_spin_enter(&callout_lock);
> 606
> 607 /*
> 608 * We can't touch 'c' here because it might
> be
> 609 * freed already. If LWPs waiting for
> callout
>
> > it seems it called mutex_spin_enter instead
> > of mutex_spin_exit.
>
> The return address points the address where the program goes
> back, so it points the next address of what it was executing
> in the previous stack frame.
>
> So, I guess "func" has a pointer to the mutex_vector_exit
> function. And kernel called it at line 604 above. Then,
> the kernel crashed inside the function pointed by "func
> (=mutex_vector_exit())".
Is is probably a tail call generated by the compiler. For example:
myfunc(void)
{
mutex_enter(&foo);
/* do stuff */
mutex_exit(&foo);
return;
}
The last call can be turned into "jmp mutex_exit" by the compiler. Can you
try compiling the kernel with -O0? It will not make those optimizations.
Thanks,
Andrew
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