> Why are you adding a value to the break and using brk, anyway, rather
> than just using sbrk?  It sure looks to me as though what you're trying
> to do is a perfect match to sbrk()'s semantics.

Because I'm looking for a problem with brk(), not sbrk(). Anyway, it
seems that sbrk() is juste a library call that is translated into brk().

-- 
Emmanuel Dreyfus.  
Pas de processeur Intel, pas de logiciels Microsoft:
Des programmes sains dans un ordinateur sain.
p99dreyf@criens.u-psud.fr