On Tue, 22 Dec 1998, Tim Rightnour wrote:

: double i;
: float j;
: 
: i = 12.0 / 0;
: printf("i: %f\n", i);
: j = 12.0 / 0;
: printf("j: %f\n", j);

This is not legal ANSI C, and "gcc -Wformat" should tell you about it.

The argument of %f is a double, not a float - what you end up with is a
double containing the bits of j and a float-sized array of random bits off
the stack.

The correct last statement should read:

printf("j: %f\n", (double)j);

-- 
-- Todd Vierling (Personal tv@pobox.com; Bus. todd_vierling@xn.xerox.com)