Subject: bin/10379: sh expands $? incorrectly within backticks
To: None <gnats-bugs@gnats.netbsd.org>
From: Andreas Gustafsson <gson@nominum.com>
List: netbsd-bugs
Date: 06/16/2000 14:04:18
>Number: 10379
>Category: bin
>Synopsis: sh expands $? incorrectly within backticks
>Confidential: no
>Severity: serious
>Priority: medium
>Responsible: bin-bug-people
>State: open
>Class: sw-bug
>Submitter-Id: net
>Arrival-Date: Fri Jun 16 14:05:00 PDT 2000
>Closed-Date:
>Last-Modified:
>Originator: Andreas Gustafsson
>Release: Jun 13, 2000
>Organization:
Nominum Inc.
>Environment:
System: NetBSD trebuchet.rc.vix.com 1.4ZD NetBSD 1.4ZD (TREBUCHET) #0: Tue Jun 13 19:34:23 PDT 2000 gson@trebuchet.rc.vix.com:/usr/src/sys/arch/i386/compile/TREBUCHET i386
>Description:
When used within backticks, the shell variable $? expands to 0
even if the previous shell command exited witih a nonzero status.
>How-To-Repeat:
Type
sh -c 'false; echo `echo "$?"`'
On NetBSD-current, this prints 0, which is incorrect. On NetBSD 1.4
and the half dozen other Unix-like systems I have tried, it correctly
prints an nonzero value.
>Fix:
Not known.
>Release-Note:
>Audit-Trail:
>Unformatted: