The following reply was made to PR toolchain/33924; it has been noted by GNATS.

From: Luke Mewburn <lukem@NetBSD.org>
To: gnats-bugs@NetBSD.org
Cc: toolchain-manager@netbsd.org, gnats-admin@netbsd.org,
	netbsd-bugs@netbsd.org
Subject: Re: toolchain/33924: feature request: makefs(8) should output blocks used by each file
Date: Thu, 6 Jul 2006 09:04:56 +1000

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 On Wed, Jul 05, 2006 at 10:20:00PM +0000, tg@mirbsd.org wrote:
   | If a file is split across several filesystem blocks,
   | say, blocks 8, 9 and 11, and we assume a fs block is
   | 4096 bytes (8 sectors), the file then occupies the
   | sectors 64-71, 72-79, and 88-95. The optimal output
   | format would have them already concatenated, so it
   | would look like this:
   |=20
   | path/to/ourfile X 64 79 88 95
   |=20
   | The 'X' here is some kind of separator, in case the
   | filenames contain spaces. It should be user-selectable.
   | (Or do you guys have a better idea?)
 
 You could just use a space separator, and use the vis(3)
 encoding already used by the mtree format for the filename.
 (This format is used by the "-F specfile" makefs option)
 
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