Subject: Re: accuracy of "long double"
To: Neil Booth <neil@daikokuya.co.uk>
From: Matthias Drochner <M.Drochner@fz-juelich.de>
List: port-amd64
Date: 08/20/2007 15:17:52
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neil@daikokuya.co.uk said:
> b) Exponents have a wider range, so overflows or underflows that
> would happen on doubles don't necessarily happen on long
> doubles.
Yes, I had figured that too, see my second reply to the PR.
> d) Despite many claims to the contrary that you will read on the
> net, and on GCC lists, there is no double-rounding problem.
The famous "paranoia" test program finds a number of rounding
flaws eg on Linux. I've extracted the failing tests for
multiplication - see attachment.
The tests succeed on NetBSD. If I set the FPCW to its initial
value, ie 64-bit rounding (by enabling the "#if 0" part),
the tests fail. With -mfpmath=sse, the tests succeed.
So doubles are still not rounded correctly if the FPU is used
in extended precision mode.
best regards
Matthias
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#include <stdio.h>
#include <float.h>
#define FLOAT double
#define EPSILON DBL_EPSILON
FLOAT Zero = 0.0, One = 1.0, OneAndHalf = 1.5;
FLOAT T, X, Y, Y1, Y2, Z;
FLOAT U2 = EPSILON; /* probed in "paranoia" */
int
mult1()
{
Y2 = One + U2;
X = OneAndHalf - U2;
Z = (X - U2) * Y2;
Z = Z - X;
return (Z == Zero);
}
int
mult2()
{
Y1 = One - U2;
X = OneAndHalf - U2;
Y = OneAndHalf + U2;
T = Y * Y1;
T = T - X;
return (T <= Zero);
}
int
main()
{
#if 0
const int fpcw = 0x37f;
asm("fldcw %0"::"m"(fpcw));
#endif
if (!mult1())
printf("* rounding error 1\n");
if (!mult2())
printf("* rounding error 2\n");
return 0;
}
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