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Re: CVS commit: src/sys/dev/hpc
On Tue, Sep 18, 2018 at 18:52:34 +0900, Rin Okuyama wrote:
> On 2018/09/18 18:21, Valery Ushakov wrote:
> > On Tue, Sep 18, 2018 at 12:17:41 +0900, Rin Okuyama wrote:
> >
> > > > @@ -278,8 +279,10 @@ hpckbd_keymap_setup(struct hpckbd_core *
> > > > * XXX The way this is done is really wrong. The __UNCONST()
> > > > * is a hint as to what is wrong. This actually ends up modifying
> > > > * initialized data which is marked "const".
> > > > + *
> > > > * The reason we get away with it here is that on sh3 kernel
> > > > - * is directly mapped.
> > > > + * is directly mapped. For mips, read-only data is mapped
> > > > + * read/write at the moment.
> > > > */
> >
> > Is this distinction necessary? My guess would be that on mips the
> > reason it works is exactly the same: the kernel is directly mapped
> > i.e. we bypass MMU for these accesses.
> >
> > If that's indeed the case, the "at the moment" part of the comment
> > would be misleading, as there's no other moment in the future where it
> > becomes false.
> >
> > Please, can you clarify?
>
> Sorry for ambiguous expression. I'm not a mips guy and I should
> confirm this before commit. This function is called before
> pmap_bootstrap(). Does this mean that your argument is true?
> If so, I will update the comment.
I think sh3 (the hardware) mostly copied mips memory organization, so
I *guess* our kernel works more or less the same on both in this
regard. So I pmap_bootstrap will later set up the MMU for things like
malloc, but - I *guess* - the kernel itself still remains directly
mapped (va == pa, no MMU translation or permission checks).
But I know nothing about mips :)
-uwe
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