Subject: Re: 1.5S vs sparc/MP
To: None <pk@cs.few.eur.nl>
From: Simon J. Gerraty <sjg@quick.com.au>
List: tech-smp
Date: 03/07/2001 01:31:33
> kernel lock? Should probably have the sleeper decrement sleepers when
> he wakesup, rather than when sema_signal calls wakeup_one(), I'll try
> that shortly.
That didn't seem to make any difference...
{0}sema_clear(0xf02b1544) count==0, sleepers==0
[BREAK]
Stopped at cpu_Debugger+0x4: jmpl [%o7 + 0x8], %g0
db{0}> ps
PID PPID PGRP UID S FLAGS COMMAND WAIT
5 0 0 0 3 0xa0204 aiodoned semvseg
4 0 0 0 3 0xa0204 ioflush syncer
3 0 0 0 3 0x20204 reaper reaper
2 0 0 0 3 0xa0204 pagedaemon pgdaemo
1 0 1 0 3 0x84004 init vmmaplk
0 -1 0 0 3 0xa0204 swapper schedul
db{0}> x/x cache_semaphore
cache_semaphore: 0
db{0}>
cache_semaphore+0x4: f02371c8
db{0}>
cache_semaphore+0x8: 0
db{0}>
cache_semaphore+0xc: 0
db{0}>
cache_semaphore+0x10: 0
db{0}>
cachestats: 88
db{0}> x/s f02371c8
openboot_special4m.194+0x498: semcflush
But for laughs, lets call wakeup_one():
db{0}> call wakeup_one(cache_semaphore)
0xf02b1544
db{0}> ps
PID PPID PGRP UID S FLAGS COMMAND WAIT
5 0 0 0 2 0xa0204 aiodoned
4 0 0 0 3 0xa0204 ioflush syncer
3 0 0 0 3 0x20204 reaper reaper
2 0 0 0 3 0xa0204 pagedaemon pgdaemo
1 0 1 0 3 0x84004 init vmmaplk
0 -1 0 0 3 0xa0204 swapper schedul
That looks better...
db{0}> c
[BREAK]
Stopped in pid 1 (init) at cpu_Debugger+0x4: jmpl [%o7 + 0
x8], %g0
db{0}> ps
PID PPID PGRP UID S FLAGS COMMAND WAIT
5 0 0 0 2 0xa0204 aiodoned
4 0 0 0 3 0xa0204 ioflush syncer
3 0 0 0 3 0x20204 reaper reaper
2 0 0 0 3 0xa0204 pagedaemon pgdaemo
>1 0 1 0 7 0x84004 init
0 -1 0 0 3 0xa0204 swapper schedul
db{0}>
As does that, we have init SONPROC - presumably spinning for the
kernel lock? Is there an easy way to see who has it?
Thanks
--sjg