Subject: Re: bug in handling of != in make?
To: None <tech-userlevel@NetBSD.org>
From: Roland Illig <rillig@NetBSD.org>
List: tech-userlevel
Date: 06/09/2006 08:53:21
Klaus Heinz wrote:
> Hi,
>
> given a file test.txt containing the line
>
> $NetBSD$
>
> and the Makefile
>
> ----------------
> VERSION!= sed -ne 's/^.*\(\$$NetBSD.*\$$\).*$$/\1/p' test.txt > /tmp/sed.txt; cat /tmp/sed.txt
>
> all:
> @echo '${VERSION}'
> @cat /tmp/sed.txt
> ----------------
VERSION_cmd= echo '$$NetBSD$$'
VERSION= ${VERSION_cmd:sh}
all:
echo ${VERSION:Q}
This is the BSD Make equivalent to using $(shell echo '$$NetBSD$$') in
GNU Make. They both do not further expand '$' characters from the output.
The question whether someone might rely on the current behaviour of the
!= operator to mangle the output remains valid though.
Roland